AP EAMCET · PHYSICS · Work Power Energy
A lift raises 50 passengers each having average weight \(600 \mathrm{~N}\) to a height of \(100 \mathrm{~m}\) at a constant speed in time \(t\). If the average power of \(15 \mathrm{~kW}\) is required by the lift, then the value of \(t\) in seconds is
- A \(150\)
- B \(100\)
- C \(300\)
- D \(200\)
Answer & Solution
Correct Answer
(D) \(200\)
Step-by-step Solution
Detailed explanation
We know that, Power \(=\frac{\text { Work done }}{\text { Time }}\) \(\Rightarrow P=\frac{W}{t}=\frac{F \times s}{t}\) \(\Rightarrow \quad P=\frac{m g h}{t}\) ...(i) Here, weight of passengers \(=m g=50 \times 600 \mathrm{~N}\) height, \(h=100 \mathrm{~m}\) Power,…
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