AP EAMCET · Maths · Probability
Two persons \(A\) and \(B\) throw a pair of dice alternately until one of them gets the sum of the numbers appeared on the dice as 4 and the person who gets this result first is declared as the winner. If A starts the game: then the probability that \(B\) wins the game is
- A \(\frac{11}{23}\)
- B \(\frac{1}{2}\)
- C \(\frac{5}{11}\)
- D \(\frac{8}{17}\)
Answer & Solution
Correct Answer
(A) \(\frac{11}{23}\)
Step-by-step Solution
Detailed explanation
Outcomes for sum 4 are \((1,3),(3,1),(2,2)\) Probability of sum \(4=\frac{3}{36}=\frac{1}{12}\)…
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