AP EAMCET · PHYSICS · Current Electricity
In a potentiometer, the area of cross section of the wire is \(4 \mathrm{~cm}^2\), the current flowing in the circuit is 1 A and the potential gradient is \(7.5 \mathrm{Vm}^{-1}\), then the resistivity of the potentiometer wire is
- A \(3 \times 10^{-3} \Omega \mathrm{~m}\)
- B \(2 \times 10^{-6} \Omega \mathrm{~m}\)
- C \(4 \times 10^{-2} \Omega \mathrm{~m}\)
- D \(5 \times 10^{-4} \Omega \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(3 \times 10^{-3} \Omega \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
In potentiometer, \(\mathrm{A}=4 \mathrm{~cm}^2=4 \times 10^{-4} \mathrm{~m}^2\) \(\mathrm{I}=1 \mathrm{~A}, \mathrm{k}=7.5 \mathrm{Vm}^{-1}\) \(\therefore\) Potential gradient, \(k=\frac{V}{l}=\frac{I_\delta}{A}\) \(\therefore\) Resistivity…
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