AP EAMCET · PHYSICS · Magnetic Effects of Current
A short magnet oscillates with a time period 0.1 s at a place where horizontal magnetic field is \(24 \mu \mathrm{~T}\). A downward current of 18 A is established in a vertical wire kept at a distance of 20 cm east of the magnet. The new time period of oscillations of the magnet is
- A 0.1 s
- B 0.089 s
- C 0.076 s
- D 0.057 s
Answer & Solution
Correct Answer
(C) 0.076 s
Step-by-step Solution
Detailed explanation
\(\mathrm{T}_1=0.1 \mathrm{~s}, \mathrm{~B}_{\mathrm{H}}=24 \mu \mathrm{~T}=24 \times 10^{-6} \mathrm{~T}, \mathrm{I}=18 \mathrm{~A}\), \(\mathrm{r}=20 \mathrm{~cm}=20 \times 10^{-2} \mathrm{~m}\) Magnetic field due to vertical wire,…
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