AP EAMCET · PHYSICS · Current Electricity
A galvanometer having 30 divisions has a current sensitivity of \(0.0625 \frac{\text { div }}{\mu \mathrm{A}}\). If it is converted into a voltmeter to read a maximum of 6 V, then the resistance of that voltmeter is
- A \(7.5 \mathrm{k} \Omega\)
- B \(12.5 \mathrm{k} \Omega\)
- C \(6 \mathrm{k} \Omega\)
- D \(5 \mathrm{k} \Omega\)
Answer & Solution
Correct Answer
(B) \(12.5 \mathrm{k} \Omega\)
Step-by-step Solution
Detailed explanation
\(I_g = \frac{\text{Number of divisions}}{\text{Current sensitivity}} = \frac{30 \text{ div}}{0.0625 \frac{\text{div}}{\mu \text{A}}} = 480 \, \mu \text{A} = 480 \times 10^{-6} \text{ A}\)…
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