AP EAMCET · PHYSICS · Electromagnetic Waves
The oscillating electric field of an electromagnetic wave is given by \(E_y=30 \sin \left(2 \times 10^{11} t+300 \pi x\right) \mathrm{Vm}^{-1}\). Then, the value of wavelength of the electromagnetic wave is
- A \(5.67 \times 10^{-3} \mathrm{~m}\)
- B \(6.67 \times 10^{-3} \mathrm{~m}\)
- C \(66.7 \times 10^{-3} \mathrm{~m}\)
- D \(7.66 \times 10^{-3} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(6.67 \times 10^{-3} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
From equation of wave, \(k=\) wave number \(=300 \pi\) Also, \(\begin{aligned} & k=\frac{2 \pi}{\lambda} \\ & \lambda=\frac{2 \pi}{k}=\frac{2 \pi}{300 \pi}=6.67 \times 10^{-3} \mathrm{~m} \end{aligned}\)
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