AP EAMCET · PHYSICS · Wave Optics
In Young's double slit experiment, the slits separated by \(0.6 \mathrm{~mm}\) are illuminated with light of \(6600 Å\). Interference pattern is obtained on a screen placed at \(4 \mathrm{~m}\) from slits. The minimum distance from the central maximum at which the average intensity is \(50 \%\) of the maximum value is
- A \(0.21 \mathrm{~mm}\)
- B \(2.1 \mathrm{~mm}\)
- C \(0.11 \mathrm{~mm}\)
- D \(1.1 \mathrm{~mm}\)
Answer & Solution
Correct Answer
(D) \(1.1 \mathrm{~mm}\)
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