AP EAMCET · PHYSICS · Ray Optics
In a compound microscope, the focal lengths of two lenses are \(1.5 \mathrm{~cm}\) and \(6.25 \mathrm{~cm}\). An object is placed at \(2 \mathrm{~cm}\) from the objective and the final image is formed at \(25 \mathrm{~cm}\) from the eye lens. The distance between the two lenses is .............. (in \(\mathrm{cm}\) ).
- A 6
- B 7.75
- C 9.25
- D 11
Answer & Solution
Correct Answer
(D) 11
Step-by-step Solution
Detailed explanation
For, objective, \( u=-2 \mathrm{~cm}, f=1.5 \mathrm{~m} \) By \(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\), we have, \( \frac{1}{v}=\frac{1}{1.5}-\frac{1}{2} v=6 \mathrm{~cm} \) For eyepiece, \( v=-25 \mathrm{~cm}, f=6.25 \mathrm{~cm} \)…
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