AP EAMCET · PHYSICS · Electromagnetic Induction
A current carrying circular loop is perpendicular to a magnetic field of induction \(10^{-4} \mathrm{~T}\). If the radius of the loop starts shrinking at a uniform rate of \(2 \mathrm{mms}^{-1}\), then the emf induced in the loop at the instant, when its radius is \(20 \mathrm{~cm}\) will be
- A \(0.02 \pi \mu \mathrm{V}\)
- B \(0.08 \pi \mu \mathrm{V}\)
- C \(0.03 \pi \mu \mathrm{V}\)
- D \(0.05 \pi \mu \mathrm{V}\)
Answer & Solution
Correct Answer
(B) \(0.08 \pi \mu \mathrm{V}\)
Step-by-step Solution
Detailed explanation
Given, \(B=10^{-4} \mathrm{~T}, r=20 \mathrm{~cm}=20 \times 10^{-2} \mathrm{~m}\) \[ \frac{d r}{d t}=-\frac{2 \mathrm{~mm}}{\mathrm{~s}}=-2 \times 10^{-3} \frac{\mathrm{m}}{\mathrm{s}} \] Induced emf,…
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