AP EAMCET · Maths · Probability
Three squares of a chessboard are selected at random. The probability of selecting two squares of one colour and the other of a different colour is equal to
- A \(\frac{10}{17}\)
- B \(\frac{15}{19}\)
- C \(\frac{17}{23}\)
- D \(\frac{16}{21}\)
Answer & Solution
Correct Answer
(D) \(\frac{16}{21}\)
Step-by-step Solution
Detailed explanation
Total number of ways of selecting 3 square \(=64_{\mathrm{C}_3}\) Total number of ways of selecting 2 square of one colour and other square of different colour \(=(2\) white, 1 black \()\) or (1 white, 2 black \()\)…
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