AP EAMCET · PHYSICS · Communication System
A TV transmitter has a range of \(50 \mathrm{~km}\). The height of the TV transmitter is _________ (Radius of the earth, \(R_e=6 \cdot 4 \times \overline{10^6 \mathrm{~m} \text {) }}\)
- A 195.3 m
- B 186.5 m
- C 206 m
- D 175 m
Answer & Solution
Correct Answer
(A) 195.3 m
Step-by-step Solution
Detailed explanation
Range, \(d=\sqrt{2 R_e h_T}\) \(\begin{gathered} 50 \mathrm{~km}=\sqrt{2 \times 6.4 \times 10^6 \times h_T} \\ 2500 \times 10^6=128 \times 10^5 h_T \\ \frac{25000}{128}=h_T \\ h_T=195.3 \end{gathered}\)
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