AP EAMCET · PHYSICS · Magnetic Effects of Current
A circular coil of 30 turns and radius \(8 \mathrm{~cm}\) carrying a current of \(6 \mathrm{~A}\) is suspe-ded vertically in a uniform horizontal magnetic field of magnitude \(1.0 \mathrm{~T}\). The field lines make an angle of \(20^{\circ}\) with the normal of the coil. The magnitude of the counter torque that must be applied to prevent the coil from turning is
- A \(5.4 \mathrm{Nm}\)
- B \(7.2 \mathrm{Nm}\)
- C \(3.6 \mathrm{Nm}\)
- D \(1.8 \mathrm{Nm}\)
Answer & Solution
Correct Answer
(D) \(1.8 \mathrm{Nm}\)
Step-by-step Solution
Detailed explanation
Number of turns, \(\mathrm{N}=30\) turns Radius, \(\mathrm{r}=8 \mathrm{~cm}=0.08 \mathrm{~m}\) Current, \(\mathrm{i}=6 \mathrm{~A}\) Magnetic field, \(\mathrm{B}=1 \mathrm{~T}\) The magnitude of the counter tarque will be…
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