AP EAMCET · PHYSICS · Laws of Motion
Four blocks \(A, B, C\) and \(D\) of masses \(6 \mathrm{~kg}, 3 \mathrm{~kg}\), \(6 \mathrm{~kg}\) and \(\mathrm{I} \mathrm{kg}\) respectively are connected by light strings passing over frictionless pulleys as shown in the figure. The strings \(P\) and \(Q\) are horizontal. The coefficient of friction between the horizontal surface and the block \(B\) is 0.2 and the blocks \(A\) and \(B\) move together. If the system is released from rest then the tension in the string \(Q\) is (Acceleration due to gravity, \(g=10 \mathrm{~ms}^{-2}\))
- A \(48 \mathrm{~N}\)
- B \(24 \mathrm{~N}\)
- C \(12 \mathrm{~N}\)
- D \(6 \mathrm{~N}\)
Answer & Solution
Correct Answer
(C) \(12 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Given, \(m_A=6 \mathrm{~kg}, m_B=3 \mathrm{~kg}, m_C=6 \mathrm{~kg}\), and \(m_D=1 \mathrm{~kg}\) and coefficient of friction between block \(B\) and horizontal surface, \(\mu=0.2\) Now, the acceleration of complete system,…
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