AP EAMCET · PHYSICS · Magnetic Properties of Matter
A material of \(0.25 \mathrm{~cm}^2\) cross-sectional area is placed in a magnetic field of strength \((\mathrm{H}) 1000 \mathrm{Am}^{-1}\). Then, the magnetic flux produced is
(Susceptibility of material is 313)
(Permeability of free space, \(\mu_0=4 \pi \times 10^{-7} \mathrm{Hm}^{-1}\) )
- A \(8.33 \times 10^{-8} \mathrm{~Wb}\)
- B \(1.84 \times 10^{-6} \mathrm{~Wb}\)
- C \(9.87 \times 10^{-6} \mathrm{~Wb}\)
- D \(3.16 \times 10^{-6} \mathrm{~Wb}\)
Answer & Solution
Correct Answer
(C) \(9.87 \times 10^{-6} \mathrm{~Wb}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Magnetic flux } \phi=B A=\mu H A \\ & =\mu_0\left(1+\chi_{\mathrm{m}}\right) H A\left[\because \mu=\mu_0\left(1+\chi_m\right)\right] \\ & =4 \pi \times 10^{-3} \times(1+313) \times 1000 \times 0.25 \times 10^{-4} \\ & =9.87 \times 10^{-6}…
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