AP EAMCET · PHYSICS · Magnetic Effects of Current
A proton, a deuteron (nucleus of \({ }_1 \mathrm{H}^2\) ) and an \(\alpha\)-particle with same kinetic energy enter a region of uniform magnetic field moving at right angles to the field. The ratio of the radii of their circular paths is :
- A \(1: 2: 4\)
- B \(1: \sqrt{2}: 1\)
- C \(2: \sqrt{2}: 1\)
- D \(1: 1: 2\)
Answer & Solution
Correct Answer
(B) \(1: \sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
\(r=\frac{m v}{q B}=\frac{\sqrt{2 m K}}{q B}\) \(\Rightarrow \quad r \propto \frac{(m)^{1 / 2}}{q}\) \(\therefore \quad r_p=\frac{\left(m_p\right)^{1 / 2}}{q_p}, r_d=\frac{\left(m_d\right)^{1 / 2}}{q_d}\) and \(\quad r_\alpha=\frac{\left(m_\alpha\right)^{1 / 2}}{q_\alpha}\)…
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