AP EAMCET · Maths · Quadratic Equation
If \(\alpha_1, \alpha_2, \alpha_3, \alpha_4, \alpha_5\) are the roots of \(x^5-5 x^4+9 x^3-9 x^2\) \(+5 x-1=0\) then \(\frac{1}{\alpha_1^2}+\frac{1}{\alpha_2^2}+\frac{1}{\alpha_3^2}+\frac{1}{\alpha_4^2}+\frac{1}{\alpha_5^2}=\)
- A \(15\)
- B \(\frac{1}{7}\)
- C \(7\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(7\)
Step-by-step Solution
Detailed explanation
\(x^5-5 x^4+9 x^3-9 x^2+5 x-1=0\) ...(i) \(\because a_0 x^{\mathrm{n}}+a_1 x^{\mathrm{n}-1}+a_2 x^{\mathrm{n}-2}+\ldots .+a_{\mathrm{n}-1} x+a_{\mathrm{n}}=0\) Here \(a_0=-a_{\mathrm{n}}, a_1=-a_{\mathrm{n}-1}\) is class II reciprocal equation. So, eq (i) is an odd degree…
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