AP EAMCET · Maths · Limits
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Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
The series is given as, =limn→∞13·7+17·11+111·15+…+n terms =limn→∞1443·7+47·11+411·15… =limn→∞1413-17+17-111+111-115+…1n+1n-1n+4 =limn→∞1413-1n+4…
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