AP EAMCET · Chemistry · s Block Elements
In the hardening stage of plaster of paris, the compound formed is
- A \(\mathrm{CaSO}_4\)
- B \(Orthorhombic\) \(\mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}\)
- C \(\mathrm{CaSO}_4 \cdot \mathrm{H}_2 \mathrm{O}\)
- D \(Monoclinic\) \(\mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}\)
Answer & Solution
Correct Answer
(D) \(Monoclinic\) \(\mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}\)
Step-by-step Solution
Detailed explanation
Plaster of paris absorb water to form monoclinic gypsum which is a hard substance. \[ \mathrm{CaSO}_4 \cdot \frac{1}{2} \mathrm{H}_2 \mathrm{O} \stackrel{3 / 2 \mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O} \] (monoclinic gypsum)
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