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AP EAMCET · PHYSICS · Thermal Properties of Matter

A calorimeter contains \(0.5 \mathrm{~kg}\) of water at \(30^{\circ} \mathrm{C}\). When \(0.3 \mathrm{~kg}\) of water at \(60^{\circ} \mathrm{C}\) is added to it, the resulting temperature is found to be \(40^{\circ} \mathrm{C}\). The water equivalent of the calorimeter is

  1. A \(0.25 \mathrm{~kg}\)
  2. B \(0.1 \mathrm{~kg}\)
  3. C \(0.2 \mathrm{~kg}\)
  4. D \(0.25 \mathrm{~kg}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.1 \mathrm{~kg}\)

Step-by-step Solution

Detailed explanation

Temperature of cold water in calorimeter, \(T_1=30^{\circ} \mathrm{C}, m_1=0.5 \mathrm{~kg}=500 \mathrm{~g}\) Temperature of hot water, \(T_2=60^{\circ} \mathrm{C}\), \(m_2=0.3 \mathrm{~kg}=300 \mathrm{~g}\) Resulting temperature, \(T_3=40^{\circ} \mathrm{C}\) Let water…
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