AP EAMCET · PHYSICS · Nuclear Physics
In the Uranium radioactive series, the initial nucleus is \({ }_{92}^{238} \mathrm{U}\) and final nucleus is \({ }_{82}^{206} \mathrm{~Pb}\). When the Uranium nucleus decays to lead, the number of \(\alpha\)-particles emitted is .......... and the number of \(\beta\)-particles emitted is ____.
- A 6,8
- B 8,6
- C 16,6
- D 32,2
Answer & Solution
Correct Answer
(B) 8,6
Step-by-step Solution
Detailed explanation
According to question, Initial nuclei \(={ }_{92}^{238} \mathrm{U}\) Final nuclei \(={ }_{82}^{206} \mathrm{~Pb}\) Change in atomic number \(=92-82=10\) When an \(\alpha\)-particle emits from a nuclei, then its atomic number is decreased by 2 units and atomic mass is decreased…
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