AP EAMCET · PHYSICS · Thermodynamics
A Carnot heat engine absorbs 600 J of heat from a source at a temperature of \(127^{\circ} \mathrm{C}\) and rejects 400 J of heat to a sink in each cycle. The temperature of the sink is
- A 266.7 K
- B 166.7 K
- C 133.3 K
- D \(333.3 \mathrm{~K}\)
Answer & Solution
Correct Answer
(A) 266.7 K
Step-by-step Solution
Detailed explanation
\(T_H = 127 + 273 = 400 \mathrm{~K}\) \(\frac{Q_L}{Q_H} = \frac{T_L}{T_H}\) \(T_L = \frac{400}{600} \times 400 \mathrm{~K}\) \(T_L = 266.7 \mathrm{~K}\)
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