AP EAMCET · PHYSICS · Magnetic Effects of Current
A rectangular loop of sides 25 cm and 10 cm carrying a current of 10 A is placed with its longer side parallel to a long straight conductor 10 cm apart carrying current 25 A. The net force on the loop is
- A \(6.25 \times 10^{-5} \mathrm{~N}\)
- B \(5.5 \times 10^{-5} \mathrm{~N}\)
- C \(3.75 \times 10^{-5} \mathrm{~N}\)
- D \(8.75 \times 10^{-11} \mathrm{~N}\)
Answer & Solution
Correct Answer
(A) \(6.25 \times 10^{-5} \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Due to symmetry, \(\begin{aligned} & \mathrm{F}_3=\mathrm{F}_4 \\ & \mathrm{~F}_1=\frac{\mu_0 \mathrm{I}_1 \mathrm{I}_2 1}{2 \pi \mathrm{r}_1} \\ & \mathrm{~F}_2=\frac{\mu_0 \mathrm{I}_1 \mathrm{I}_2 1}{2 \pi \mathrm{r}_2} \end{aligned}\) \(\therefore \quad\) Net force on the…
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