AP EAMCET · PHYSICS · Laws of Motion
A block of mass 2 kg is placed on a rough horizontal surface. If a horizontal force of 20 N acting on the block produces an acceleration of \(7 \mathrm{~m} \mathrm{~s}^{-2}\) in it, then the coefficient of kinetic friction between the block and the suface is (Aceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A \(0.2\)
- B \(0.3\)
- C \(0.4\)
- D \(0.5\)
Answer & Solution
Correct Answer
(B) \(0.3\)
Step-by-step Solution
Detailed explanation
\(N = mg\) \(N = 2 \times 10 = 20 \mathrm{~N}\) \(F - \mu_k N = ma\) \(20 - \mu_k (20) = 2 \times 7\) \(20 - 20\mu_k = 14\) \(20\mu_k = 6\) \(\mu_k = \frac{6}{20} = 0.3\)
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