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AP EAMCET · PHYSICS · Oscillations

The displacement of a simple harmonic motion of amplitude 6 cm when its kinetic energy is equal to its potential energy is

  1. A \(2 \sqrt{2} \mathrm{~cm}\)
  2. B 2 cm
  3. C \(3 \sqrt{2} \mathrm{~cm}\)
  4. D \(\frac{3}{\sqrt{2}} \mathrm{~cm}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3 \sqrt{2} \mathrm{~cm}\)

Step-by-step Solution

Detailed explanation

Given, amplitude of oscillation, a = 6 cm Let displacement be x cm. When kinetic energy is equal to potential energy, then…