AP EAMCET · Maths · Permutation Combination
A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is
- A \(196\)
- B \(140\)
- C \(168\)
- D \(176\)
Answer & Solution
Correct Answer
(A) \(196\)
Step-by-step Solution
Detailed explanation
Total number of questions \(=13\) Now of questions to be selected \(=10\) Restriction - At least 4 from first 5 questions are to be selected. Case I If exactly 4 out of first 5 questions are selected. Number of ways of selecting 4 questions from 5 questions \(={ }^5 C_4=5\)…
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