AP EAMCET · PHYSICS · Capacitance
When a \(0.75 \mu \mathrm{F}\) capacitor is charged to a voltage of \(20 \mathrm{~V}\), then the magnitude of charge on each plate is
- A \(15 \mu \mathrm{C}\)
- B \(10 \mu \mathrm{C}\)
- C \(20 \mu \mathrm{C}\)
- D \(12 \mu \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(15 \mu \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given that, capacitance of capacitor, \[ C=0.75 \mu \mathrm{F} \] Voltage applied, \(V=20 \mathrm{~V}\) Using an expression of charge stored on each plate of capacitor, \(Q=C V\) Substituting the values, we get…
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