AP EAMCET · PHYSICS · Electromagnetic Induction
In the given electrical circuit, if the switch \(S\) is closed then the maximum energy stored in the inductors is:
- A 3 J
- B 9 J
- C 12 J
- D 6 J
Answer & Solution
Correct Answer
(A) 3 J
Step-by-step Solution
Detailed explanation
In figure below, if switch \(S\) is open then total energy stored in the capacitors, is suppose \(E_0\). Energy in IF capacitor, \( E_1=\frac{1}{2} C V^2=\frac{1}{2} C\left(\frac{Q}{C}\right)^2=\frac{1}{2} \frac{Q^2}{C}=\frac{1}{2} \times \frac{4^2}{1}=8 \mathrm{~J} \)…
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