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AP EAMCET · PHYSICS · Laws of Motion

A block of mass 1.5 kg kept on a rough horizontal surface is given a horizontal velocity of \(10 \mathrm{~ms}^{-1}\). If the block comes to rest after travelling a distance of 12.5 m , the coefficient of kinetic friction between the surface and the block is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )

  1. A 0.2
  2. B 0.4
  3. C 0.8
  4. D 0.6
Verified Solution

Answer & Solution

Correct Answer

(B) 0.4

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{u}=10 \mathrm{~ms}^{-1}, \mathrm{~m}=1.5 \mathrm{~kg} \\ & \mathrm{a}=\frac{\mathrm{f}}{\mathrm{m}}=\frac{\mu \mathrm{mg}}{\mathrm{m}}=\mathrm{Mg}\end{aligned}\) \(\therefore\) Stopping distance, \(S=\frac{u^2}{2 a}\)…