AP EAMCET · PHYSICS · Thermodynamics
A Carnot engine operating between temperatures \(600 \mathrm{~K}\) and \(300 \mathrm{~K}\), absorbs \(800 \mathrm{~J}\) of heat from the source. The mechanical work done per cycle is
- A \(400 \mathrm{~J}\)
- B \(650 \mathrm{~J}\)
- C \(750 \mathrm{~J}\)
- D \(600 \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(400 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\eta=1-\frac{300}{600}=1-\frac{1}{2}=\frac{1}{2}\) Now, \(w=\eta Q=\frac{1}{2} \times 800=400 J\)
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