AP EAMCET · PHYSICS · Mechanical Properties of Solids
The pressure required to decrease the volume of \(4000 \mathrm{cc}\) water by \(0.05 \%\) is
(Bulk modulus of water \(=2.2 \times 10^9 \mathrm{Nm}^{-2}\) )
- A \(11 \times 10^6 \mathrm{Nm}^{-2}\)
- B \(5 \times 10^5 \mathrm{Nm}^{-2}\)
- C \(2.2 \times 10^6 \mathrm{Nm}^{-2}\)
- D \(1.1 \times 10^6 \mathrm{Nm}^{-2}\)
Answer & Solution
Correct Answer
(D) \(1.1 \times 10^6 \mathrm{Nm}^{-2}\)
Step-by-step Solution
Detailed explanation
Volume of water, \(\mathrm{V}=4000 \mathrm{cc}\) decrease of volume, \(\frac{\Delta V}{V}=0.05 \%=0.0005\) Bulk modulus, \(B=2.2 \times 10^9 \mathrm{~N} / \mathrm{m}^2\) Bulk modulus is given as:…
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