AP EAMCET · PHYSICS · Semiconductors
Truth table for the given circuit is
- A \(\begin{array}{lll}\mathrm{A} & \mathrm{B} & \mathrm{Y} \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{array}\)
- B \(\begin{array}{lll}\mathrm{A} & \mathrm{B} & \mathrm{Y} \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1\end{array}\)
- C \(\begin{array}{lll}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{array}\)
- D \(\begin{array}{lll}A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{array}\)
Answer & Solution
Correct Answer
(C) \(\begin{array}{lll}A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1\end{array}\)
Step-by-step Solution
Detailed explanation
The output of the logic gate circuit is…
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