AP EAMCET · Maths · Three Dimensional Geometry
\(R\) divides the line joining two points \(P\) and \(Q\) whose position vectors are \(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}\) and \(-\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}\) respectively in the ratio \(2: 1\) externally. \(S\) divides \(P Q\) internally in the ratio \(2: 1\). Then, the position vector of the midpoint of the line joining \(R\) and \(S\) is
- A \(\frac{-5}{3} \hat{\mathbf{i}}-\frac{2}{3} \hat{\mathbf{j}}-\frac{5}{3} \hat{\mathbf{k}}\)
- B \(\frac{-5}{3} \hat{\mathbf{i}}+\frac{2}{3} \hat{\mathbf{j}}+\frac{5}{3} \hat{\mathbf{k}}\)
- C \(\frac{5}{3} \hat{\mathbf{i}}-\frac{2}{3} \hat{\mathbf{j}}-\frac{5}{3} \hat{\mathbf{k}}\)
- D \(\frac{5}{3} \hat{\mathbf{i}}+\frac{2}{3} \hat{\mathbf{j}}+\frac{5}{3} \hat{\mathbf{k}}\)
Answer & Solution
Correct Answer
(B) \(\frac{-5}{3} \hat{\mathbf{i}}+\frac{2}{3} \hat{\mathbf{j}}+\frac{5}{3} \hat{\mathbf{k}}\)
Step-by-step Solution
Detailed explanation
We have, \(P=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}\) and \(Q=-\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}\) \(R\) divides externally in the ratio \(2: 1\)…
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