AP EAMCET · Maths · Ellipse
The line \(3 x+4 y-5=0\) cuts the curve \(2 x^2+3 y^2=5\) at \(A\) and \(B\). If ' \(O\) ' is the origin, then \(\angle A O B=\)
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{\pi}{8}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
Given equation of line is \(\begin{aligned} 3 x+4 y-5 & =0 \\ \frac{3 x+4 y}{5} & =1 \quad \ldots (i) \end{aligned}\) Equation of curve is \(2 x^2+3 y^2=5\) ...(ii) Homogenising Eq. (ii) using Eq. (i)…
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