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AP EAMCET · Maths · Permutation Combination

Statement I The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is \({ }^9 C_3\).
Statement II The number of ways of choosing 3 places from 9 different places is \({ }^9 \mathrm{C}_3\).

  1. A Statement I is true, statement II is true, statement II is not a correct explanation for statement I
  2. B Statement I is true, statement II is false
  3. C Statement I is false, statement II is true
  4. D Statement I is true, statement II is true, statement II is a correct explanation for statement I
Verified Solution

Answer & Solution

Correct Answer

(A) Statement I is true, statement II is true, statement II is not a correct explanation for statement I

Step-by-step Solution

Detailed explanation

Statement I The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is \({ }^9 C_3\). \(\because n\) identical things can be distributed to different boxes by \({ }^{t-1} C_{r-1}\) ways such that no box is empty. 10 identical balls can…