AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The correct increasing order of number of lone pair of electrons on the central atom of \(\mathrm{SnCl}_2, \mathrm{XeF}_2, \mathrm{CIF}_3\) and \(\mathrm{SO}_3\) is
- A \(\mathrm{SO}_3 \lt \mathrm{CIF}_3 \lt \mathrm{SnCl}_2 \lt \mathrm{XeF}_2\)
- B \(\mathrm{SO}_3 \lt \mathrm{SnCl}_2 \lt \mathrm{CIF}_3 \lt \mathrm{XeF}_2\)
- C \(\mathrm{XeF}_2 \lt \mathrm{SnCl}_2 \lt \mathrm{CIF}_3 \lt \mathrm{SO}_3\)
- D \(\mathrm{XeF}_2 \lt \mathrm{CIF}_3 \lt \mathrm{SnCl}_2 \lt \mathrm{SO}_3\)
Answer & Solution
Correct Answer
(B) \(\mathrm{SO}_3 \lt \mathrm{SnCl}_2 \lt \mathrm{CIF}_3 \lt \mathrm{XeF}_2\)
Step-by-step Solution
Detailed explanation
\begin{array}{|c|c|c|c|}\hline \text{Molecule} & \begin{array}{c} \text{Valence electron} \\ \text{of CMI} \end{array} & \begin{array}{c} \text{Lone} \\ \text{pair} \end{array} & \begin{array}{c} \text{Bond} \\ \text{pair} \end{array} \\ \hline \mathrm{SnCl}_2 & 4 & 1 & 2 \\…
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