AP EAMCET · PHYSICS · Magnetic Effects of Current
A short bar magnet of magnetic moment \(10^4 \mathrm{~J} \mathrm{~T}^{-1}\) is free to rotate in a horizontal plane. The work done in rotating the magnet slowly from the direction parallel to a horizontal magnetic field of \(4 \times 10^{-5} \mathrm{~T}\) to a direction \(60^{\circ}\) to the direction of the field is
- A 0.2 J
- B 2.6 J
- C 0.4 J
- D 6.2 J
Answer & Solution
Correct Answer
(A) 0.2 J
Step-by-step Solution
Detailed explanation
\(W = -MB(\cos \theta_2 - \cos \theta_1)\) \(W = -(10^4)(4 \times 10^{-5})(\cos 60^{\circ} - \cos 0^{\circ})\) \(W = -(0.4)(0.5 - 1)\) \(W = -0.4(-0.5)\) \(W = 0.2 \mathrm{~J}\)
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