AP EAMCET · Maths · Three Dimensional Geometry
The foot of the perpendicular drawn from a point A \((1,1,1)\) on to a plane \(\pi\) is \(P(-3,3,5)\). If the equation of the plane parallel to the plane \(\pi\) and passing through the midpoint of AP is \(a x-y+c z+d=0\), then \(a+c-d=\)
- A \(-10\)
- B \(5\)
- C \(-12\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(-10\)
Step-by-step Solution
Detailed explanation
Since, the foot of the perpendicular to the plane \(\pi\) is \(\mathrm{P}(-3,3,5)\). Therefore, \(\mathrm{P}(-3,3,5)\) lies on \(\pi\). Also, direction ratios of the perpendicular line AP is \((-4,2,4)\). So, equation of \(\pi\) is…
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