AP EAMCET · Maths · Trigonometric Ratios & Identities
\(\frac{1}{\sin 1^{\circ} \sin 2^{\circ}}+\frac{1}{\sin 2^{\circ} \sin 3^{\circ}}+\ldots\)
\(+\frac{1}{\sin 89^{\circ}+\sin 90^{\circ}}=\)
- A \(\frac{\cos 1^{\circ}}{\sin 1^{\circ}}\)
- B \(\frac{\cos 1^{\circ}}{\sin ^2 1^{\circ}}\)
- C \(\frac{\sin 1^{\circ}}{\cos 1^{\circ}}\)
- D \(\frac{\sin ^2 1^{\circ}}{\cos 1^{\circ}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\cos 1^{\circ}}{\sin ^2 1^{\circ}}\)
Step-by-step Solution
Detailed explanation
Here, \(\frac{1}{\sin 1^{\circ} \sin 2^{\circ}}+\frac{1}{\sin 2^{\circ} \sin 3^{\circ}}+\ldots+\frac{1}{\sin 89^{\circ} \sin 90^{\circ}}\)…
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