AP EAMCET · Maths · Circle
The abscissae of two points \(P, Q\) are the roots of the equation \(2 x^2+4 x-7=0\) and their ordinates are the roots of the equation \(3 x^2-12 x-1=0\). Then the centre of the circle with \(P Q\) as a diameter is
- A \((-1,2)\)
- B \((-2,6)\)
- C \((1,-2)\)
- D \((2,-6)\)
Answer & Solution
Correct Answer
(A) \((-1,2)\)
Step-by-step Solution
Detailed explanation
Since, it is given that abscissae of two point \(P, Q\) are roots of the equation \(2 x^2+4 x-7=0\) and their ordinates are the roots of the equation \(3 x^2-12 x-1=0\). Let \(P\left(x_1, y_1\right)\) and \(Q\left(x_2, y_2\right)\), then \(x_1+x_2=-2 \text { and } y_1+y_2=4\)…
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