AP EAMCET · Maths · Parabola
If \((2,3)\) is the vertex and.' \((3,2)\) is the focus of a parabola, then its equation is
- A \(x^2+2 x y+y^2-18 x-2 y+35=0\)
- B \(2 x^2+4 x y+2 y^2-9 x-y+17=0\)
- C \(x^2+2 x y+y^2-18 x-2 y+17=0\)
- D \(x^2+4 x y+4 y^2-18 x+2 y+9=0\)
Answer & Solution
Correct Answer
(C) \(x^2+2 x y+y^2-18 x-2 y+17=0\)
Step-by-step Solution
Detailed explanation
\(\because \quad\) Vertex \(\mathrm{O} \equiv(2,3)\) focus \(\mathrm{S} \equiv(3,2)\) \(\because \mathrm{O}\) is the mid point AS \(\therefore \frac{\mathrm{x}_1+3}{2}=2\) and \(\frac{\mathrm{y}_1+2}{2}=3\) \(\Rightarrow x_1=1, y_1=4\) Slope of AS, \(m_1=\frac{2-3}{3-2}=-1\)…
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