AP EAMCET · PHYSICS · Electromagnetic Induction
The coefficient of mutual inductance between the primary and the secondary coil of a transformer is \(0.2 \mathrm{H}\). When the current in the primary changes by \(5 \mathrm{As}^{-1}\), then the induced emf in the secondary will be
- A \(5 \mathrm{~V}\)
- B \(1 \mathrm{~V}\)
- C \(25 \mathrm{~V}\)
- D \(10 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(1 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given, coefficient of mutual induction, \(M=0.2 \mathrm{H}\) The rate of change in current in primary coil. \(\frac{d I}{d t}=5 \mathrm{As}^{-1}\) \(\therefore\) Induced emf in the secondary coil, \(e=M \frac{d I}{d t}=0.2 \times 5=1 \mathrm{~V}\)
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