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AP EAMCET · Maths · Circle

If the circles \(x^2+y^2-8 x-8 y+28=0\) and \(x^2+y^2-8 x-6 y\) \(+25-\alpha^2=0\) have only one common tangent, then \(\alpha=\)

  1. A \(\alpha=4\)
  2. B \(\alpha=2\)
  3. C \(\alpha=1\)
  4. D \(\alpha=5\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\alpha=1\)

Step-by-step Solution

Detailed explanation

\(S_1=x^2+y^2-8 x-8 y+28=0\) \(\Rightarrow C_1=(4,4), r_1=\sqrt{16+16-28}=2\) \(S_2=x^2+y^2-8 x-6 y+25-\alpha^2=0\) \(\Rightarrow C_2=(4,3), r_2=\sqrt{16+9-25+\alpha^2}=\alpha\) Condition for one common tangent is…
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