AP EAMCET · Maths · Circle
If the circles \(x^2+y^2-8 x-8 y+28=0\) and \(x^2+y^2-8 x-6 y\) \(+25-\alpha^2=0\) have only one common tangent, then \(\alpha=\)
- A \(\alpha=4\)
- B \(\alpha=2\)
- C \(\alpha=1\)
- D \(\alpha=5\)
Answer & Solution
Correct Answer
(C) \(\alpha=1\)
Step-by-step Solution
Detailed explanation
\(S_1=x^2+y^2-8 x-8 y+28=0\) \(\Rightarrow C_1=(4,4), r_1=\sqrt{16+16-28}=2\) \(S_2=x^2+y^2-8 x-6 y+25-\alpha^2=0\) \(\Rightarrow C_2=(4,3), r_2=\sqrt{16+9-25+\alpha^2}=\alpha\) Condition for one common tangent is…
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