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AP EAMCET · Maths · Quadratic Equation

If \(a, b\) and \(c\) are the roots of \(x^3+4 x+1=0\), then \(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{c+a}=\)

  1. A 2
  2. B 3
  3. C 4
  4. D -4
Verified Solution

Answer & Solution

Correct Answer

(C) 4

Step-by-step Solution

Detailed explanation

\(a, b, c\) are roots of \(x^3+4 x+1=0\) \[ \begin{aligned} \Rightarrow & x^3+0 \cdot x^2+4 x+1=0 \\ \text { So, } & a+b+c=0 \Rightarrow a b c=-1 \end{aligned} \] \[ \text { and } a b+b c+c a=4 \] Now,…