AP EAMCET · PHYSICS · Oscillations
When a body of mass \(8 \mathrm{~kg}\) is attached to a spring balance, the reading of the balance is \(20 \mathrm{~cm}\). Instead of \(8 \mathrm{~kg}\), if another body of mass \(M\) is suspended from the spring balance and is made to oscillate vertically, the time period of oscillation is \(\frac{\pi}{5} \mathrm{~s}\), then the value of \(\mathrm{M}\) is
(Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(4 \mathrm{~kg}\)
- B \(6 \mathrm{~kg}\)
- C \(8 \mathrm{~kg}\)
- D \(9 \mathrm{~kg}\)
Answer & Solution
Correct Answer
(A) \(4 \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
Mass of body, \(\mathrm{m}=8 \mathrm{~kg}\) Period of oscillation, \(\mathrm{T}=\frac{\pi}{5} \mathrm{~s}\) Reading of the balance, \(x=20 \mathrm{~cm}=0.2 \mathrm{~m}\) For mass \(8 \mathrm{~kg}\) \(\mathrm{mg}=\mathrm{kx} \Rightarrow \mathrm{k}=\frac{\mathrm{mg}}{\mathrm{x}}\)…
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