AP EAMCET · Maths · Indefinite Integration
\(\int \frac{\sin 2 x}{\sin ^2 x+3 \cos x-3} d x\)
- A \(2 \log \left|\frac{\cos x-2}{\cos x-1}\right|+c\)
- B \(\log \left(\frac{(\cos x-2)^2}{(\cos x-1)^4}\right)+c\)
- C \(\log \left(\frac{(\cos x-2)^2}{|\cos x-1|}\right)+c\)
- D \(\log \left(\frac{(\cos x-2)^4}{(\cos x-1)^2}\right)+c\)
Answer & Solution
Correct Answer
(D) \(\log \left(\frac{(\cos x-2)^4}{(\cos x-1)^2}\right)+c\)
Step-by-step Solution
Detailed explanation
\( \int \frac{\sin 2 x}{\sin ^2 x+3 \cos x-3} d x \) \( = \int \frac{2 \sin x \cos x}{1-\cos^2 x+3 \cos x-3} d x \) \( = \int \frac{2 \sin x \cos x}{-(\cos^2 x-3 \cos x+2)} d x \) Let \( u=\cos x \), then \( du=-\sin x \, dx \).…
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