AP EAMCET · Maths · Straight Lines
The distance between the lines \(3 x+4 y=9\) and \(6 x+8 y=15\) is
- A \(\frac{3}{2}\)
- B \(\frac{3}{10}\)
- C \(6\)
- D \(\frac{3}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{3}{10}\)
Step-by-step Solution
Detailed explanation
To find, distance between the lines \(3 x+4 y=9\) and \(6 x+8 y=15\), since we know that distance between the lines \(a x+b y+c_1=0\) and \(a x+b y+c_2=0\) \(\Rightarrow \quad d=\left|\frac{c_1-c_2}{\sqrt{a^2+b^2}}\right|\) Here lines are \(3 x+4 y-9=0\) and…
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