AP EAMCET · Maths · Statistics
If for a distribution, \(\Sigma(x-5)=3\) and \(\Sigma(x-5)^2=43\) and total number of observations is 18 , then the variance of the distribution is
- A 2.16
- B 3.16
- C 2.36
- D 3.36
Answer & Solution
Correct Answer
(C) 2.36
Step-by-step Solution
Detailed explanation
Given \(\Sigma(x-5)=3\) and \(\Sigma(x-5)^2=43\) Number of observations (n) = 18 To Find Variance = ? \(\begin{aligned} \because \text { Variance } & =\frac{\Sigma\left(x_i-\bar{x}\right)^2}{n} \\ & =\frac{\Sigma(x-5)^2}{18}=\frac{43}{18}=2.36\end{aligned}\)
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