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AP EAMCET · PHYSICS · Mechanical Properties of Fluids

In a hydraulic lift, compressed air exerts a force F on a small piston of radius 3 cm. Due to this pressure the second piston of radius 5 cm lifts a load of 1875 kg. The value of F is
(Acceleration due to gravity =10 m s-2)

  1. A 1250 N
  2. B 125 N
  3. C 6750 N
  4. D 675 N
Verified Solution

Answer & Solution

Correct Answer

(C) 6750 N

Step-by-step Solution

Detailed explanation

The principle for hydraulic lifts is based on Pascal's law. Pressure on both the piston will be same, F1A=F2A ⇒F1π×3×10-22=Fπ×5×10-22⇒F9=1875×1025⇒F=6750 N
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