AP EAMCET · Maths · Differential Equations
The general solution of the differential equation \(\left(y^2+x+1\right) d y=(y+1) d x\) is
- A \(x+2+(y+1) \log (y+1)^2=y+c\)
- B \(x+2+\log (y+1)^2=\frac{y}{y+1}+c\)
- C \(\frac{x}{y+1}=\log (y+1)^2+y+c\)
- D \(\frac{x+2}{y+1}+\log (y+1)^2=y+c\)
Answer & Solution
Correct Answer
(D) \(\frac{x+2}{y+1}+\log (y+1)^2=y+c\)
Step-by-step Solution
Detailed explanation
\(\frac{d x}{d y}=\frac{y^2+x+1}{y+1} \Rightarrow \frac{d x}{d y}-\frac{x}{y+1}=\frac{y^2+1}{y+1}\) If \(=e^{\int-\frac{1}{y+1} d y}=\frac{1}{y+1} \frac{x}{y+1}=\int \frac{y^2+1}{(y+1)^2} d y=\int\left(1-\frac{2 y}{(y+1)^2}\right) d y\)…
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