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AP EAMCET · Maths · Circle

The circle \(x^2+y^2-6 x-10 y+p=0\) neither intersects nor touch the coordinate axes and the point \((1,4)\) lies inside the circle. Then the range of possible values of ' \(p\) ' is

  1. A \(23 < p < 25\)
  2. B \(25 < p < 29\)
  3. C \(21 < p < 23\)
  4. D \(12 < p < 21\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(25 < p < 29\)

Step-by-step Solution

Detailed explanation

The equation of given circle is \(\begin{array}{rlrl} x^2+y^2-6 x-10 y+p & =0 \\ \Rightarrow & \quad(x-3)^2+(y-5)^2 & =34-p \end{array}\) \(\therefore\) The point \((1,4)\) lies inside the circle, so…