AP EAMCET · Maths · Circle
The circle \(x^2+y^2-6 x-10 y+p=0\) neither intersects nor touch the coordinate axes and the point \((1,4)\) lies inside the circle. Then the range of possible values of ' \(p\) ' is
- A \(23 < p < 25\)
- B \(25 < p < 29\)
- C \(21 < p < 23\)
- D \(12 < p < 21\)
Answer & Solution
Correct Answer
(B) \(25 < p < 29\)
Step-by-step Solution
Detailed explanation
The equation of given circle is \(\begin{array}{rlrl} x^2+y^2-6 x-10 y+p & =0 \\ \Rightarrow & \quad(x-3)^2+(y-5)^2 & =34-p \end{array}\) \(\therefore\) The point \((1,4)\) lies inside the circle, so…
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